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《中小学数学》(初中版)2014年第4期李世荣老师的文章《给“狼题”一个和谐高效的分析法》(以下简称原文),抓住矩形折叠的数学本质,深入探究2012年天津中考第25题,并给出简洁的通俗解法(以下简称“和谐分析法”),令人拍手称快.原题呈现:(2 012天津)已知一个矩形纸片OACB,将该纸片放置在平面直角坐标系中,点A(11,0),点B(0,6),点P为BC边上的动点(点P不与点B、C重合),经过点O,P折叠该纸片,得点B′和折痕
“Elementary and middle school mathematics” (junior high school edition) in 2014 fourth Li Shirong’s article “give ” wolf title “a harmonious and efficient analysis method” (hereinafter referred to as the original text), seize the mathematical nature of the rectangular fold, in-depth exploration 2012 Tianjin Tianjin Normal University test 25 questions, and gives a concise popular solution (hereinafter referred to as “Harmony Analysis ”), make clap cheeks. Original title shows: (2,012 Tianjin) known a rectangular paper OACB, the The paper is placed in a rectangular coordinate system, point A (11,0), point B (0,6), point P is the moving point on the edge of BC (point P does not coincide with point B, C) P Punch the piece, point B ’, and fold