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本刊文〔１〕关于分式和的不等式：若ａ１≥ａ２≥…≥ａｎ＞０，０＜ｂ１≤ｂ２≤…≤ｂｎ；或０＜ａ１≤ａ２≤…≤ａｎ，ｂ１≥ｂ２≥…≥ｂｎ＞０，则ａ１ｂ１＋ａ２ｂ２＋…＋ａｎｂｎ≥ｎ（ａ１＋ａ２＋…＋ａｎ）ｂ１＋ｂ２＋…＋ｂｎ．本文将其推广为：对于ｐ≥１...
This article [1] about the fractional sum inequality: if a1≥a2≥...≥an>0,00, then a1b1+a2b2+...+anbn≥n(a1+a2+...+an)b1+b2+...+bn. This article will be promoted as: for p ≥ 1...