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制备以β-环糊精(β-CD)为主体,2,2′,5,5′-四氯联苯胺(TCB)为客体的固态包合物,通过核磁共振氢谱(~1H NMR)和红外光谱(FT-IR)分析了包合物的形成。利用紫外吸收光谱研究了β-CD及其衍生物羧甲基-β-环糊精(CMBCD)对TCB的包合行为,并用Job法和Benesi-Hildebrand双倒数法分别获得β-CD及CMBCD与TCB之间的包合比和包合常数。结果表明,β-CD和CMBCD均可与TCB形成包合比为1:1的包合物,包合常数分别为727.9 L·mol~(-1)和1647L·mol~(-1),且经羧甲基修饰之后的β-环糊精对TCB的包合能力明显优于β-环糊精。
The solid clathrates containing β-cyclodextrin (β-CD) as the main body and 2,2 ’, 5,5’-tetrachlorobenzidine (TCB) as the guest were prepared by 1H NMR (1H NMR) And infrared spectroscopy (FT-IR) analysis of the inclusion complex formation. The inclusion behavior of β-CD and its derivative carboxymethyl-β-cyclodextrin (CMBCD) on TCB was studied by ultraviolet absorption spectroscopy. The β-CD and CMBCD were obtained by the Job and Benesi-Hildebrand double reciprocal method TCB between the inclusion ratio and inclusion constant. The results showed that both β-CD and CMBCD could form an inclusion complex with TCB of 1: 1 with the inclusion constants of 727.9 L · mol -1 and 1647 L · mol -1, respectively, and The β-cyclodextrin modified by carboxymethyl group was significantly better than β-cyclodextrin on inclusion of TCB.