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通过薄壁管复合加载实验及单向拉伸卸载组合实验,证明了Zn-22Al合金在超塑温度-速度条件下遵循Mises屈服条件,且与应变速度呈(σ_1-σ_2)~2+(σ_2-σ_3)~2+(σ_3-σ_1)~2=2(σ=K_(ε~m))~2的关系。给出了该合金在250℃、应变速度为3.3×10~(-2)(sec~(-1))时,平面应力且0.2％应变时的屈服椭圆方程为通过单向拉伸位置预置自动卸载组合实验及数学回归分析处理,可定量地确定关系式(变形一定时,σ=K_(ε~m)),且证明K、m与变形程度或变形速度有关。通过薄壁管复合加载实验和分析,还得到薄壁筒形件吹塑时的吹塑压力-应力图和压力-应变图,可为判断和选择类似的吹塑成型力学条件提供参考。
Through the combined experiments of thin-walled tube and uniaxial tensile unloading, the results show that the Mises yield condition of Zn-22Al alloy under the condition of superplastic temperature-velocity follows (σ 1 -σ 2) ~ 2 + (σ 2 -σ_3) ~ 2 + (σ_3-σ_1) ~ 2 = 2 (σ = K_ (ε ~ m)) ~ 2. The yield elliptic equation of plane stress and 0.2% strain at 250 ℃ and strain rate of 3.3 × 10 ~ (-2) s is given. Automatic unloading combined experiments and mathematical regression analysis process can be quantitatively determine the relationship (certain deformation, σ = K_ (ε ~ m)), and prove that K, m and the degree of deformation or deformation speed. Through the thin-walled tube composite loading experiment and analysis, the blown pressure-stress diagram and pressure-strain diagram of the thin-walled cylinder are obtained, which can be used as a reference for judging and selecting similar blow molding mechanical conditions.