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题目.一质点做速度逐渐增大的匀加速直线运动,在时间间隔t内位移为s,动能变为原来的9倍.该质点的加速度为(A)s/t~2.(B)3s/2t~2.(C)4s/t~2.(D)8s/t~2.分析:本题题干简洁,但信息量大.留给考生思考的角度较多,也就有多种解法.由质点在时间间隔t内位移为s,可以运用匀变速直线运动的规律求解;由质点动能变,可以运用动能定理求解;由质点动能变可以计算其动量变化,也可以运用
The topic of a point to do the speed of uniform acceleration of linear motion, the displacement of the time interval t s, kinetic energy becomes 9 times the original acceleration of the particle (A) s / t ~ 2 (B) 3s /2t~2.(C)4s/t~2.(D)8s/t~2. Analysis: The title of the dry concise, but the large amount of information left to the examinee more perspective, there are a variety of solutions . The displacement of the particle in the time interval t is s, which can be solved by the law of uniform linear motion. The kinetic energy of the particle changes and can be solved by the kinetic energy theorem. The momentum change of the particle can be used to calculate the change of momentum,