在高中的物理教学中,有时会遇到有关喷泉喷水时功率的计算,对此问题教学实践中出现了下面两种不同的结论.让我们通过一具体的实例,共同来辨别其真伪,弄清其本质.例题:有一个喷泉,可将水喷至高度为h处,在空中共有质量为m的水,求此喷泉喷水的功率?解法1:功率P1=Wt1,W1=m2gh,t=22g In the physics teaching of high school, we sometimes encounter the calculation of the power when the fountain water is sprayed. There are two different conclusions in this teaching practice. Let us identify the authenticity through a concrete example. Clarify its nature. Example: There is a fountain that can spray water to a height of h. There is a mass of water in the sky. Find the power of this fountain. Solution 1: Power P1=Wt1, W1=m2gh, t=22g