题在直角三角形中,a,b,c为其三边长,其中c为斜边,若h为斜边上的高,求证:a+bc+h.本题的证明只要通过分析法即可完成,从不等式的方向来看是否存在最大的正常数λ使得:λ(c+h)≤a+b恒成立呢?我们不妨设直角三角形的一个锐角为∠A=θ图1(如图1),则有h=bsinθ,a=btanθ,c=cobsθ,代 In the right triangle, a, b, c for its long sides, where c is the hypotenuse, if h is the height of the hypotenuse, verify: a + bc + h. Proof of the problem as long as the analysis can be done , From the direction of the inequality whether there is a maximum normal number λ such that: λ (c + h) ≤ a + b constant holds? We may wish to set right-angled triangle an acute angle ∠A = θ Figure 1 (Figure 1) , Then h = bsinθ, a = btanθ, c = cobsθ, generation