题:当 x=2-3~(1/2),求代数式:(7+43~(1/2))x~2+(2+3~(1/2))x+3~(1/2)的值.解等此题一般是直接把 x 的值代入所求式进行计算.而事实上,只要善于将7+43~(1/2)变形为(2+3~(1/2))~2,这题应用代入法也的确是非常简单的.但如果我们设想把各项系数变化一下,比如把二次项系数7+43~(1/2)改变为11+73~(1/2),把一次项系数改成3+ Problem: When x=2-3~(1/2), find the algebraic expression:(7+43~(1/2))x~2+(2+3~(1/2))x+3~(1) The value of /2), solution, etc. This problem is generally calculated by directly substituting the value of x into the required formula. In fact, as long as you are good at transforming 7+43~(1/2) into (2+3~(1/) 2))~2. This application substitution method is indeed very simple. But if we imagine changing the coefficients, for example, change the quadratic term coefficient 7+43~(1/2) to 11+73~ (1/2), change the coefficient of one item to 3+