论文部分内容阅读
数学中有一个著名的“3x+1猜想”.它是说:“设n是一个正整数.如果它是偶数,就用2去除它,如果它是奇数,就用3去乘它再加1.这样算下去,有限次后必定得1”.例如:
There is a well-known “3x + 1 guess” in mathematics. It says: “Let n be a positive integer. If it is even, remove it with 2, and if it is odd, multiply it by 3 Plus 1. In this way, a limited number must be 1 ”. For example: