题目如图1,已知C为线段月刀上一点,分别以AC、CB为边向AB的同旁作正三角形ACD和正三角形CBE. 求证:月E一BD.① (初二几何课本P,1‘第13题) 分析要证八E一召D,只要证△八CE里△工不B,由于AC一石犯,CE~CB,则只要证匕八CE一艺Z兀B.而匕l一/2一600, 艺1十艺3~/2+艺3,即艺ACE一艺五 The problem is shown in Fig. 1. Known C is a point on the line knife, with AC and CB as the side-by-side AB’s same side as the positive triangle ACD and the positive triangle CBE. Proof: Month E-BD.1 (Grade 2 geometry textbook P, 1’Q.13) To analyze and prove that the eight E-calls D, as long as the certificate △ eight CE in △ work is not B, because AC a stone guilty, CE ~ CB, as long as the certificate 匕 CE CE 艺 Z兀B. One or two one thousand six hundred, art 1 ten art 3~/2+ art 3, that is art ACE one art five