在高三的一本数学复习资料中,有一道关于含向量的方程的解的存在性的问题.下面在该题求解的基础上探讨一下怎样判断和解含向量的方程.　　题目　已知a,b,c为非零向量且a⊥b,x∈R,x1,x2 是方程ax2 + bx + c=0的两实根,求证:x1=x2 .1　解法探讨错解　因为a⊥b则a·b=0 .b·(ax2 + In the high school mathematics review material, there is a problem about the existence of the solution of the equation containing the vector. Based on the solution of the problem, we will discuss how to judge and solve the equation containing the vector. The topic is known as a,b, c is a non-zero vector and a⊥b,x∈R,x1,x2 are the two real roots of the equation ax2 + bx + c=0. Prove that: x1=x2 .1 Solve for the solution because of a⊥b then a·b =0 .b·(ax2 +