一道高考题的几何解法

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1 一个不等式的几何解法在今(2003)年全国统一高考数学(理科)试卷中,有一题涉及如下一个不等式: 设:x+|x-2c|>1的解集为R。求:c的取值范围。含绝对值的不等式,基本解法是分类打开绝对值。虽说不难,但较繁,这里介绍一个几何解法,不需打开绝对值,且有形象直观的优点。因原不等式等价于 1 Geometric solution of an inequality In the current (2003) National Unified College Mathematics (Science) examination paper, there is a problem that involves the following inequality: Let x = |x-2c|>1 be the solution set R. Find the range of c: c. With an inequality of the absolute value, the basic solution is to classify and open the absolute value. Although not difficult, but more complicated, here is a geometric solution that does not need to open the absolute value, and has the advantages of visual and intuitive. Because the original inequality is equivalent to
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