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一、角元塞瓦定理设P是△ABC内任意一点(如图1),则sin∠BAP/sin∠PAC·sin∠CBP/sin∠PBA·sin∠ACP/sin∠PCB=1.
First, the angle element Seva theorem Let P be △ ABC any point (Figure 1), then sin ∠ BAP/sin ∠ PAC sin ∠ CBP/sin ∠ PBA sin ∠ ACP / sin ∠ PCB = 1.