本刊1984年第2期转载的《几何学中的四颗小明珠》,其中之一是: 如图1,在△OA_1A_2中,∠O=20°,OA_1=OA_2,∠OA_2X=20°,∠OA_1Y=30°,求∠A_2XY。在本刊1985年第1期上,安振平同志提供了一种三角解法。本文再提供几种解法。在原题设条件下,显然∠A_1A_2X=60°,∠A_1XA_2=40°, One of the four small pearls in geometry published in the 2nd issue of this volume in 1984 is: In Figure 1, in △OA_1A_2, ∠O=20°, OA_1=OA_2, and ∠OA_2X=20°. ∠OA_1Y=30°, find ∠A_2XY. In the first issue of the 1985 issue of this publication, Comrade An Zhenping provided a triangulation method. This article provides several solutions. Under the conditions of the original question, it is clear that ∠A_1A_2X=60°, ∠A_1XA_2=40°,