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由一元二次方程的求根公式,不难得到x~2 -x-1=0的两根分别为a=(1+5~(1/2))/2,b=(1-5~(1/2))/2.这两个根符合如下等式a+b=1①ab=-1②a~2=a+1③b~2=b+1④
From the root formula of a quadratic equation, it is not difficult to get the two roots of x~2 -x-1=0 as a=(1+5~(1/2))/2, b=(1-5~ (1/2))/2. These two roots conform to the following equation a+b=11ab=-12a~2=a+13b~2=b+14