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一、关于物质溶解量的计算这类计算涉及的比例式主要是两个:溶质质量:溶剂质量=溶解度:100(或溶解长=溶质质量/溶剂质量×100)溶质质量:溶液质量=溶解度:(100+溶解度)现举一例如下:例今有0℃硝酸钾饱和溶液56.9克,如果在这种溶液里加入200克水,再使温度升高到100℃。问共需加入多少克硝酸钾,才能使溶液达到饱和状态?(硝酸钾0℃的溶解度是13.3克,100℃的溶解度是246克)常见的解法有:一解:设56.9克硝酸钾饱和溶液里含有X克硝酸钾。
I. Calculation of the amount of dissolved substances This type of calculation involves two major proportions: Solute mass: Solvent mass = Solubility: 100 (or Solubility = Solute Mass / Solvent Mass × 100) Solute Mass: Solution Mass = Solubility: (100+ Solubility) An example is as follows: For example, there is 56.9 g of a saturated solution of potassium nitrate at 0°C. If 200 g of water is added to this solution, raise the temperature to 100°C. How many grams of potassium nitrate need to be added in order to make the solution reach saturation?(The solubility of potassium nitrate at 0°C is 13.3 g and the solubility at 100°C is 246 g) Common solutions: One solution: Set 56.9 g of potassium nitrate solution It contains X grams of potassium nitrate.