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数学已知二次方程 mx(x-1)+x+m-y=01)证明:m≠0的实数时,方程表示抛物线;2)对于 x 的任意值,要使 y>0,求m 的范围;3)在此范围内求此曲线顶点轨迹的标准方程,并画图;4)证明在此范围内 y 没有最小值。(高富德供稿)物理有一单摆,摆长为 l,摆锤质量为 M,挂在 O 点,摆从水平位置自由摆下,摆锤到达最低点时与一质量为 m 的物体碰撞,碰撞后摆锤以原来1/3的速度继续摆动,求物体 m 碰撞后获得的动能。
Mathematical known quadratic equation mx (x-1) + x + my = 01) Proof: When m ≠ 0 real number, the equation represents a parabola; 2) For any value of x, let y> 0, find the range of m ; 3) Find the standard equation of the curve of the vertex of the curve in this range, and draw a graph; 4) Prove that y has no minimum value in this range. (Gaofu De feed) Physics There is a single pendulum, swing length l, pendulum mass M, hanging in the O point, put freely from the horizontal position, when the pendulum reaches the lowest point of a mass m collision, collision After the pendulum to the original rate of 1/3 continue to swing, seek the kinetic energy obtained after the collision of the object m.