(一 )　　 2 0 0 0年第 9期数学问题的第 1 2 67题是 :试确定ａ0 的取值范围 ,使由递推式ａｎ+ 1 =- 3ａｎ+2 ｎ(ｎ=0 ,1 ,2 ,… )给出的数列是严格增数列 .该题提供者给出的解答有误 ,原解答是ａ0 16 .为说明ａ0 16 不正确 ,只要举个反例即可 ,例如当ａ0 =1时 ,数列 {ａｎ} (a) The 127th problem of the mathematical problem of the 9th issue of 2000 is to try to determine the range of values ​​for a0 so that the recurrence formula an+ 1 = - 3an + 2 n (n = 0, 1 , 2 ,...) The sequence given is a strictly increasing sequence. The answer given by the provider of this question is incorrect, the original answer is a0 16. To illustrate that a0 16 is incorrect, just give a counterexample, for example when a0 =1 , series {an}