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物理化学一、将25℃,1个大气压下的1升氧气(理想气体)绝热压缩到5大气压,耗费功为120卡。求:终态的T和S,以及此过程的△H和△G。已知:25℃,1个大气压下1摩尔氧气的熵 S=49.03卡·K~(-1)·摩尔~(-1); CP=7.0卡·度~(-1)·摩尔~(-1) 二、合成氨反应 1/2 N_2(气)+3/2 H_2(气)(?)NH_3(气) 在450℃时的平衡常数Kp=0.006655大气压~(-1) 氨的生成热△H°_(1,203)=-11.04千卡·摩尔~(-1) 各物质的恒压热容如下: NH_2——CP=6.189+7.787×10~(-3)T卡·度~(-1)·摩尔~(-1) N_2——Cp=6.449+1.413×10~(-3)T卡·度~(-1)·摩尔~(-1) H_2——Cp=6.947-0.200×10~(-3)T
First, 25 ℃, 1 at atmospheric pressure of 1 liter of oxygen (ideal gas) adiabatic compression to 5 atmospheres, effort was 120 cards. Find: the final T and S, and the process of △ H and △ G. It is known that the entropy S = 49.03 K · K -1 · mol -1 at 25 ° C for 1 mole of oxygen at 1 atmosphere; and CP = 7.0 K · degrees -1 · mol ~ (- 1) The equilibrium constant of 1/2 N_2 (gas) +3/2 H_2 (gas) (NH 3) at 450 ℃ for synthetic ammonia reaction Kp = 0.006655 Atmospheric pressure ~ (-1) Heat of formation of ammonia △ H ° _ (1,203) = - 11.04 kcal · mol -1 The constant pressure heat capacity of each substance is as follows: NH_2 - CP = 6.189 + 7.787 × 10 -3 T card · degree -1 · Mol - (-1) N_2 - Cp = 6.449 + 1.413 × 10 -3 T card · degree -1 · mol -1 -1 H 2 - Cp = 6.947-0.200 × 10 ~ (-1) -3) T