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氧化还原反应是中学化学学习的主线,也是高考必考的考点之一,从近几年高考试题的变化趋势来看,出现了一种难度较大以考查能力为主的新题型:求氧化产物和还原产物的物质的量比;给出陌生的物质,判断反应后的化合价或是否是氧化产物、还原产物等.尽管千变万化,但都离不开判断化合价的升降、电子的转移、电子数的守恒.下面通过几个例题,谈谈电子守恒法在化学计算中的应用.一、省去中间过程,简化计算例1 3.84 g铜和一定质量的浓硝酸反应,当铜反应完时,
Redox reaction is the main line of chemistry learning in secondary schools, but also one of the test points for the entrance exam, from the trend of recent college entrance examination examinations, there is a more difficult to test ability-based new type: seeking oxidation Product and reduction products of the material than the amount of; given unfamiliar material to determine the reaction after the valence or whether it is oxidation products, reduction products, etc. Although the ever-changing, but can not do without judging valence movements, electron transfer, electron number The following a few examples to talk about the application of electronic conservation in the chemical calculation. A, eliminating the need for intermediate processes to simplify the calculation Example 1 3.84 g of copper and a certain amount of concentrated nitric acid reaction, when the copper reaction is completed,