从图象上看　ｙ =ｆ(ｘ + 1)与 ｙ =ｆ- 1(ｘ + 1)的图象是分别将 ｙ =ｆ(ｘ)与 ｙ =ｆ- 1(ｘ)的图象向左平移一个单位所得 ,因 ｙ =ｆ(ｘ)与 ｙ =ｆ- 1(ｘ)图象关于 ｙ =ｘ对称 ,将 ｙ =ｘ向左平移一个单位得 ｙ =ｘ + 1,所以函数 ｙ =ｆ(ｘ + 1)与 ｙ =ｆ- 1(ｘ + 1)的图象关 The image from the perspective of y = f(x + 1) and y = f - 1(x + 1) is the image of y = f(x) and y = f - 1(x), respectively. By translating one unit, since y = f(x) and y = f - 1(x) images are symmetrical about y = x, y = x is shifted one unit to the left so that y = x + 1, so the function y = f Image of (x + 1) and y = f - 1 (x + 1)