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设P是△ABC内一点,∠APB-∠ACB=∠APC-∠ABC,又D,E分别是△APB和△APC的内心,证明AP,BD,CE
Let P be a point in △ABC, ∠APB-∠ACB=∠APC-∠ABC, and D,E are the interiors of △APB and △APC respectively, proving that AP, BD, CE