论文部分内容阅读
以向量为工具求空间距离和角可以避开高难度的思维和繁杂的推理,使解答过程顺畅、简捷,且解法固定．但是,其关键在于转化．一空间距离空间距离问题及其求解方法: (1)A、B两点之间的距离,可转化求向量AB的模． (2)求点O到直线CD的距离,可在CD上取一点 E,令CE=λED,由OE⊥CD或求|OE|的最小值得到参数λ值,以确定E的位置,则OE的模|OE|即为点O到直线CD的距离．
Using vector as a tool to find spatial distances and angles can avoid difficult thinking and complicated reasoning, making the solution process smooth and simple, and the solution is fixed. However, the key lies in the transformation. A space distance spatial distance problem and its solution method: (1) The distance between A and B points can be transformed into the modulus of vector AB. (2) Find the distance from the point O to the straight line CD, take a point E on the CD, let CE = λED, obtain the value of the parameter λ from OE ⊥ CD or the minimum value of |OE| to determine the position of E, then OE The modulo |OE| is the distance from the point O to the straight line CD.