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现行全日制十年制高中课本第二册第八章机械振动和机械波第四节单摆的课后习题3中提出了升降机中单摆周期的问题。题中问:“升降机里挂一个周期为T的单摆,当升降机匀加速上升的过程中单摆的周期大于T还是小于T?”对这一问题在中学物理教学中常见的解释方法是:“当升降机匀加速上升时,摆锤的“视重”增加了,即重量G=mg变成了G′=mg′=m(g+a)。因而单摆的周期(?)也就变成了(?),即周期T变小了。”但这样的解释方法并不十分令人满
The current full-time 10-year high school textbook in the second volume of the eighth chapter mechanical vibration and mechanical waves in the fourth quarter pendulum after-school exercise 3 in the lift single swing cycle problem. The question is: “A pendulum with a period of T is suspended in the elevator. When the elevator is accelerating and rising uniformly, the period of the pendulum is greater than T or less than T?” The common explanation method for this problem in middle school physics teaching is: “When the elevator accelerates uniformly, the ”weight“ of the pendulum increases, that is, the weight G = mg becomes G’ = mg’ = m(g + a), so the period (?) of the pendulum also changes. It becomes (?), that is, the period T becomes smaller.” But this method of interpretation is not very full