论文部分内容阅读
圆锥曲线中点关于直线对称问题在高考中时有出现,这类问题的解法比较灵活,学生常感到困难,甚至无从入手.现结合实例介绍这类问题的求解策略,供参考.策略1基础入手,牢记对称点求解设P(a,b)为直线l:Ax+By+C=0外一点,求点P关于直线l对称点P′的一般思路:过点P作直线l的垂线段,垂足为M,延长PM到P′,使MP′=MP,先求出线段PM所在直线方程,再与直线l的方程组成方程组求出M点
Conic midpoint on the straight line symmetry problems arise in the college entrance examination, the solution of such problems more flexible, students often feel difficult, or even impossible to start with examples are introduced to solve this type of problem solving strategy for reference. , Keep in mind that the symmetry point solution P (a, b) is a straight line l: Ax + By + C = 0 Outer point, find the point P On the straight line symmetry point P ’general idea: Defective foot for the M, PM extended to P ’, so MP’ = MP, first find the linear equation where the line segment PM, and then the equation with a straight line l equation M points