有些资料中称:如果不等式f(x)≥0的解集是A,那么不等式f(x)0的解集是A的补集.然而此命题不真,请看反例:不等式x-mx-m≥0的解集是(-∞,m)∪(m,+∞),然而不等式x-mx-m0的解集不是上述解集的补集{m},应是.习以为常的错误,如果不加以纠正,迟早会带来不良恶果的!纠正一个习以为常 Some data states that if the solution set of inequality f(x)≥0 is A, then the solution set of inequality f(x)0 is the complement of A. However, this proposition is not true, see the counterexample: Inequality x-mx- The solution set m ≥ 0 is (-∞, m) ∪ (m, + ∞), but the solution set of the inequality x-mx-m0 is not a complement {m} of the solution set described above. It should be a common mistake. If you don’t correct it, you will sooner or later have bad consequences! Correct a common mistake