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题目 已知函数 ｆ(ｘ) =1+ｓｉｎｘ -ｃｏｓｘ1+ｓｉｎｘ +ｃｏｓｘ,试判断它的奇偶性 ,求函数周期、单调区间 .分析 首先来化简下式 :1+ｓｉｎｘ -ｃｏｓｘ1+ｓｉｎｘ +ｃｏｓｘ.解法一 (由半角公式 )ｔａｎ ｘ2 =1-ｃｏｓｘｓｉｎｘ =ｓｉｎｘ1+ｃｏｓｘ.根据比例性质得
The title of the known function f (x) = 1 + sinx - cosx1 + sinx + cosx, try to determine its parity, find the function cycle, monotonic interval. Analysis first to simplify the following formula: 1 + sinx - cosx1 + sinx + cosx Solution One (by half-angle formula) tan x2 = 1 - cosxsinx = sinx1 + cosx.