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题目:已知 a×5/6=b×3/4=c×5/2(a、b、c 都是大于0的数),将 a、b、c 三个数按从小到大的顺序排列起来。分析与解:方法一已知三个乘法算式的积相等,而5/2>5/6>3/4,那么与 c 相乘的数最大,也就说明 c 最小,与 b 相乘的数最小,也就说明 b 最大,因此三个数应这样排列:b>a>c。方法二既然三个乘法算式的积相等,我们可以假设这个积是一个已知数,然后求出 a、b、c 的值,再比较其大小。比如:设 a×5/6=b×3/4=c×5/2=1,则 a=6/5,b=4/3,c=2/5,因为4/3>6/5>2/5,所以 b>a>c。
Title: Known a × 5/6 = b × 3/4 = c × 5/2 (a, b, c are all greater than 0), the a, b, c three numbers in ascending order Arrange it. Analysis and solution: Method one known three multiplication formula equal, and 5/2> 5/6> 3/4, then multiplied by the largest number of c, it shows c minimum, multiplied by the number of b Minimum, it means that b maximum, so the three numbers should be arranged like this: b> a> c. Method 2 Now that the products of the three multiplication formulas are equal, we can assume that the product is a known number and then find the values of a, b, c and compare their sizes. For example, let a = 6/5, b = 4/3, c = 2/5 because a 5/6 = bx 3/4 = cx 5/2 = 1 because 4/3> 6/5 > 2/5, so b> a> c.