《匀变速直线运动》公式规律很多,很多题的解法不是唯一的.解题过程中应注意一题多解,做到举一反三,触类旁通,加深对公式规律的理解.例题一个物体从斜面顶端(图1)开始做匀加速直线运动下滑到斜面的底端,在最初3s内经过的位移为x1,最后3s内经过的位移为x2,已知:x2-x1=1.2m;x1∶x2=3∶7.求斜面的长度. The formula of “uniform variable speed linear motion” has a lot of rules and many solutions are not the only ones. During the process of solving problems, we should pay attention to one problem and many solutions so as to make the best of one’s knowledge. 1) Start to do the uniform acceleration linear motion and slide down to the bottom of the slope. The displacement in the first 3s is x1 and the displacement in the last 3s is x2. Known as: x2-x1 = 1.2m; x1: x2 = 3: 7. Seek the length of the bevel.